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3 years ago

14

In the supply-and-demand schedule shown above, at the lowest price of $50, producers supply _____ music players and consumers de

mand _____ music players.
600, 0
50, 350
0, 500

1 answer:

jonny [76]3 years ago

4 0

The answer is 0 and 500, if you look at the 50$ column, you see 0 for Supplied Music Players and 500 for Demanded music players.

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Mrs. Madison's class recorded how many students had various types of pets. Twice the number of students who own a lizard is less

ss7ja [257]

So twice the number of students who own a lizard is represented by 2l where l is the number who own a lizard. we are given this is less than 10 so 2l<10 we can solve for l by dividing both sides by 2 to get l<5 meaning the number of students who own a lizard is less than 5

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3 years ago

The mass of an ant is 1/10 of the load, which it can carry in one try. What is the mass of the ant, if in one time it can carry

Viefleur [7K]

If you call $m$ the mass of the ant and $l$ the load, we have the equation

$m = \cfrac{l}{10}$

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$m = \cfrac{\frac{7}{250}}{10} = \cfrac{7}{250}\cdot\cfrac{1}{10} = \cfrac{7}{2500}$

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4 years ago

Please solve the table correctly.

Hitman42 [59]

Answer:

See below.

Step-by-step explanation:

No. Triangles Perimeter

1 14

2 18

3 22

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3 years ago

A jeweler is dividing

Anuta_ua [19.1K]

Answer: OPTION D: $\frac{3}{32}$

Step-by-step explanation:

By definiton, fractions have the following form:

$\frac{a}{b}$

Where "a" is called numerator and "b" is the denominator. The numerator and the denominator are Integers.

In order to solve this exercise you need to remember de Division of fractions:

$\frac{a}{b}\div\frac{d}{e}=\frac{a}{b}*\frac{e}{d}=\frac{a*e}{b*d}$

In this case, according to the information given in the exercise, you know that $\frac{3}{8}\ lb$ of rubies are divided into 4 lots.

Therefore, in order to calculate the weight in pounds of each lot, you need to divide $\frac{3}{8}\ lb$ by 4.

Then, you get the following result:

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As you can notice, this result matches with the Option D.

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3 years ago

Suppose we pick 3 students at random from a class with 10 boys and 15 girls. let x be the number of boys selected and y be the n

zheka24 [161]

The probability of the first pick to be a boy is 10/25.
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n(S)=number of ways selecting students of 25.
=²⁵C₃
=25·24·23/3·2·1
=2300
n(E)=(¹⁰C₁·¹⁵C₂)
=[10·(15·14)/2·1
=10500
P(E)=n(E)/n(S)=1050/2300=21/46

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3 years ago