The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>
Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
For Addison h=85(1/3)
Subtracting both distances we get
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
First you have to know the price of item.
EX: Say a candy car costs $1.50.
The candy bar was marked down 30%.
$1.50 x 30/100 = $.45
The item will decrease $.45.
$1.50 - $.45 = $1.05
Answer:
36 <127
(36,127°)
36 [ cos (127) + i sin (127)]
Step-by-step explanation:
w1 = 2 < 95
w2 = 18 < 32
w1 * w2
We multiply the magnitude and add the angles
w1 * w2 = 2*18 < (95+32)
=36 < 127
36 [ cos (127) + i sin (127)]
Answer:
1/0.7
Step-by-step explanation:
The expression x-y equals to 0.7 so we have to substitute 0.7 in the place of x-y....
----> 1/0.7
Dividing would make this equal to a long division answer (1.42857142857) so let's just leave it as a fraction!
I hope this helps! :)
