A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
The inverse is b. If 4x+1 .NE. 61, then x-5 .NE.10
Answer:
22°
Step-by-step explanation:
Triangle KJL ≅ Triangle MJL (RHS)
[JL = JL(common), KL = LM(given), angle KLJ = angle MLJ(given)]
we come up to the conclusion that 4x + 6 = 3x + 10
x = 4
∴angle KJL = 4(4) + 6 = 22°
Answer: i think 22 days
Step-by-step explanation:
i think that because you can feed you dog a cup a day.
