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kari74 [83]
3 years ago
13

What is the value of x enter your answer in the box

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0
There’s no attachment to this question and it can’t be answered without the attachment
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What is the correct domain for a log function?<br> A=(-∞,0]<br> B=[0,∞)<br> C=(-∞,0)<br> D=(0,∞)
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f(x)=\log(x)\\\\Domain:\\\\x > 0\to x\in(0,\ \infty)\\\\Answer:\ \boxed{D=(0,\ \infty)}

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Find the common ratio of the geometric sequence 0.1, 1, 10, 100, ... Write your answer as an integer or fraction in simplest for
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The answer is 10 because it’s multiplies by 10
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Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

8 0
3 years ago
A pizza shop delivers an extra large pizza, which is sold for $20, and costs the pizza shop $12 to make. The pizza
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Answer:

Is it bad that I'm a senior and have no idea how to do this?

Step-by-step explanation:

7 0
3 years ago
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In a study investigating a link between walking and improved​ health, researchers reported that adults walked an average of 873
Rainbow [258]

Answer:

H_0:\mu =873\\\\H_a: \mu

Step-by-step explanation:

Given : In a study investigating a link between walking and improved​ health, researchers reported that adults walked an average of 873 minutes in the past month for the purpose of health or recreation.

Claim : The true average number of minutes in the past month that adults walked for the purpose of health or recreation is lower than 873 minutes.

i.e. \mu

We know that the null hypothesis contains equal sign , then the set of hypothesis for the given situation will be :-

H_0:\mu =873\\\\H_a: \mu

4 0
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