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Stolb23 [73]
4 years ago
11

There are 1500 bees in a colony. Each month, the number of bees decreases by 12%. There are 800 flowering plants in a garden. Ea

ch month, 25 flowering plants are removed.
Part A: Write functions to represent the number of bees and the number of flowering plants throughout the months. (4 points)

Part B: How many bees are in the colony after 6 months? How many flowering plants are in the garden after the same number of months? (2 points)

Part C: After approximately how many months is the number of bees and the number of flowering plants the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
Evgen [1.6K]4 years ago
4 0
 So the answer to this question is:

A= bees: f(t) = 1500 × (0.88)∧t

 plants: g(t) = 800 - 25×t

B: (Bees) 1500 × (0.88)∧6= 696.60
After 6 months (696 bees ):
800 - 25×6 = 650 (Flowering Plants)
After 6 months:

650 flowering plants

C: 1500 × (0.88)∧t=800 - 25×t
t = 6.779965672

Answer is it will take 7 months or 6 for the bees and the plants.
Hope this helps!




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Let f be the function defined by f(x) = 3x^5-5x^3+2
sveticcg [70]
(a) When f is increasing the derivative of f is positive.

    f'(x) = 15x^4 - 15x^2 > 0
            15x^2(x^2 - 1)> 0
               x^2 - 1    > 0 (The inequality doesn't flip sign since x^2 is positive)
               x^2 > 1
    Then f is increasing when x < -1 and x > 1.

(b) The f is concave upward when f''(x) > 0.
    f''(x) = 60x^3 - 30x > 0
           30x(2x^2 - 1) > 0
             x(2x^2 - 1) > 0
            x(x^2 - 1/2) > 0
x(x - 1/sqrt(2))(x + 1/sqrt(2)) > 0

    There are four regions here. We will check if f''(x) > 0.
    x < -1/sqrt(2):     f''(-1) = -30 < 0
    -1/sqrt(2) < x < 0: f''(-0.5) = 7.5 > 0
    0 < x < 1/sqrt(2):  f''(0.5) = -7.5 < 0
    x > 1/sqrt(2):      f''(1) = 30 > 0

    Thus, f''(x) > 0 at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).
    Therefore, f is concave upward at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).

(c) The horizontal tangents of f are at the points where f'(x) = 0
    15x^2(x^2 - 1) = 0
    x^2 = 1
    x = -1 or x = 1
    f(-1) = 3(-1)^5 - 5(-1)^3 + 2 = 4
    f(1) = 3(1)^5 - 5(1)^3 + 2 = 0

    Therefore, the tangent lines are y = 4 and y = 0.
8 0
4 years ago
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Natasha2012 [34]
Eliminationg these equations gives zero ,no solution
6 0
3 years ago
How many integers between 199 and 599 are multiple of 3
Reptile [31]
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597

Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
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In short, Your Answer would be 133

Hope this helps!

8 0
3 years ago
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Santos flipped a coin 300 times. The coin landed heads up 125 times. Find the ratio of heads to total number of coin flips. Expr
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Answer:

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The V(t)=1.50(1.17)^t represents the value V (t), in dollars, of a comic book t years after its purchase in 2000. Determine the
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Answer:

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The general equation form is;

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To get the growth rate, we simply equate what we have in the bracket to 1 + r

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