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Stolb23 [73]
3 years ago
11

There are 1500 bees in a colony. Each month, the number of bees decreases by 12%. There are 800 flowering plants in a garden. Ea

ch month, 25 flowering plants are removed.
Part A: Write functions to represent the number of bees and the number of flowering plants throughout the months. (4 points)

Part B: How many bees are in the colony after 6 months? How many flowering plants are in the garden after the same number of months? (2 points)

Part C: After approximately how many months is the number of bees and the number of flowering plants the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
Evgen [1.6K]3 years ago
4 0
 So the answer to this question is:

A= bees: f(t) = 1500 × (0.88)∧t

 plants: g(t) = 800 - 25×t

B: (Bees) 1500 × (0.88)∧6= 696.60
After 6 months (696 bees ):
800 - 25×6 = 650 (Flowering Plants)
After 6 months:

650 flowering plants

C: 1500 × (0.88)∧t=800 - 25×t
t = 6.779965672

Answer is it will take 7 months or 6 for the bees and the plants.
Hope this helps!




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Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

\frac{46t + 92 + 46t}{t(t + 2)} = 24

92t + 92 = 24t² + 48t

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Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

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More can be learned about the relation between velocity, distance and time at brainly.com/question/28155966

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2 years ago
Five years ago, Victor was twice as old as his daughter Anika. In 10 years, the sum of their ages will equal 90. Find their ages
frozen [14]

Answer: 45 and 25

Step-by-step explanation:

Given

Five years ago victor was twice as old as his daughter

Suppose the current age of victor and his daughter are x and y

For five years ago

\Rightarrow (y-5)=2(x-5)\\\Rightarrow y-5=2x-10\\\Rightarrow y=2x-5\\\Rightarrow 2x-y=5\quad \ldots(i)

In 10 years sum of their ages is 90

\Rightarrow (y+10)+(x+10)=90\\\Rightarrow x+y=70\quad \ldots(ii)

On solving (i) and (ii) we get

\Rightarrow x=25,y=45

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Step-by-step explanation:

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julsineya [31]
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