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Sonbull [250]
4 years ago
14

Line A goes through (3, −1) and (−2, −6). Write the equation of the line that is perpendicular and goes through the point (−4, −

5)
Mathematics
1 answer:
Kitty [74]4 years ago
4 0

Answer:

do not know this answer plz tell me that answer

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Can somebody plz help me 15-[7+(-6)+1]^3
Sati [7]

Answer:

7.

Step-by-step explanation:

15 - [7 + (-6)+ 1]^3

Using PEMDAS:

= 15 - [ 7-6+1]^3

Next work out what is in the parentheses:

= 15  - 2*3

Now the exponential:

= 15 - 8

= 7.

8 0
3 years ago
Read 2 more answers
|x+1| = 1/5x+1<br> .......................
Mademuasel [1]

Answer:

x=0, -5/3

Step-by-step explanation:

3 0
3 years ago
A truck driver has to make a delivery at a location that is 230.2 miles away. She drives an average of 55 miles each hour for 3.
Vlad [161]

Answer:

The driver will make it to the location in the next hour

Step-by-step explanation:

First, find how many miles they traveled in 3.25 hours, by multiplying 55 by 3.25:

55(3.25)

= 178.75

Then, add 55 to this to see if the driver will make it in the next hour:

178.75 + 55

= 233.75

Since this is greater than 230.2, this means they will make it to the location.

So, the driver will make it to the location in the next hour.

5 0
3 years ago
Read 2 more answers
A research report from an independent-measures study states that there are significant differences between treatments, F(3, 48)
Flura [38]

Answer:

k = 4 ;

N = 52

Step-by-step explanation:

Given the ratio F(3, 48)

F takes in degree of freedom values; degree of freedom of groups ; degree of freedom of error

Hence,

df group or treatment = 3

df error = 48

df treatment = k - 1

k = Number of groups

3 = k - 1

3 + 1 = k - 1 + 1

4 = k

Number of treatment condition = 4

df error = N-k

N = total number of observations

48 = N - 4

48 + 4 = N - 4 + 4

52 = N

7 0
3 years ago
Find the vertical, horizontal, and slant asymptotes, if any, for f(x)=5x^3-51x^2+77x+100/x^2-11x+24
liraira [26]

Answer:

Step-by-step explanation:

Given:  f(x)=5x^3-51x^2+77x+100/x^2-11x+24

Please use parentheses to eliminate any ambiguity:

           

      f(x) = (5x^3-51x^2+77x+100) / (x^2 - 11x + 24)

or (better yet):

                  5x^3-51x^2+77x+100

        f(x) = ---------------------------------

                      x^2 - 11x + 24

The vertical asymptotes here are at the zeros of the denominator:

x^2 - 11x + 24 = 0,  This quadratic equation has coefficients a = 1, b = -11 and c = 24.  Thus, its roots (zeros) are:

       -(-11) ± √( 121 - 4(1)(24) )

x = -------------------------------------

                    2(1)

or:

        11 ± √( 25 )

x = --------------------

                 2

or:  x = 8 and x = 3

The vertical asymptotes are x = 8 and x = 3.

If we attempt to divide x^2 - 11x + 24 into 5x^3 - 51x^2 + 77x + 100, we see that the first term of the quotient is 5x.  As x increases or decreases without bound, 5x goes to either ∞ or -∞, so we conclude that there is no horiz. asymptote.  Continuing this division results in:

5x + 4 + a fraction

This represents the slant asymptote, y = 5x + 4

7 0
3 years ago
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