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gladu [14]
3 years ago
6

What’s the solution?

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

See balanced equations below

Explanation:

1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)

This is a single replacement reaction, involving an acid with a metal

2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂

3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)

4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)

B.

1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)

2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction

3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)

4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)

5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl

6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)

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<h2>answer.</h2>

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8 0
4 years ago
How does one determine an empirical formula from a percent composition apex?
Amiraneli [1.4K]
To assume the empirical formula of a compound, you want the ratio of the moles of every element, and you discover that by means of the percent’s of the element as the element's mass.
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To look for the moles of carbon in that sample, you would distribute the mass by the atomic mass of carbon, so 16/12 = 1.3 moles. You do the similar calculation with the other elements. For Sulfur, you divide 84g by the atomic mass of sulfur, so 84/32 = 2.6moles of sulfur. You endure in this same way if there is more than 2 elements.
Lastly you find the ratio of the moles of every element. The unassuming way to do this is to look the element with the smallest number of moles and split the other moles by that number. In the above example 2.6 moles of Sulfur divided by 1.3 moles of Carbon equals 2. (Which is a 2:1 ratio) Therefore there is twice as numerous sulfurs as carbons in this compound, and the empirical formula is CS2.
8 0
3 years ago
Read 2 more answers
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