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mixas84 [53]
2 years ago
9

Angelica calculated the distance between the two points shown on the graph below. (1st picture)

Mathematics
2 answers:
Alex Ar [27]2 years ago
7 0
Use the distance formula to find the value of the side lengths.
d=√((x1-x2)²+(y1-y2)²

d of side AC is 6

d of side CB is 10 

Angela's use of the Pythagorean Theorem of 10²+6²+c² is incorrect; she put the right values in the wrong spots, the formula needed is:
6²+10²=c²

Option C- Angelica's side lengths were too long.
scoray [572]2 years ago
6 0

Answer:

(D) last option: Angelica made an error substituting the values into the Pythagorean theorem. The equation should be.

Step-by-step explanation:


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Claire Judice
Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, -4i or 4i.

Step-by-step explanation:

Given:

The equation to solve is given as:

5x^5+6x^4+80x^3+96x^2=0

Factoring x^2 from all the terms, we get:

x^2(5x^3+6x^2+80x+96)=0

Now, rearranging the terms, we get:

x^2(5x^3+80x+6x^2+96)=0

Now, factoring 5x from the first two terms and 6 from the last two terms, we get:

x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0

Now, equating each factor to 0 and solving for 'x', we get:

x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, -4i or 4i.

4 0
3 years ago
Solve the following systems of 3-variable linear equations.​
Dima020 [189]

Answer:

.

Step-by-step explanation:

3 0
3 years ago
What is the equation of the line that passes through the point (-4,-2) and has a slope of -1/2
vampirchik [111]

Answer: y=-1/2x-4

Step-by-step explanation:

If you use point slope formula you get

y+2=-1/2(x+4)

simplify that in y=mx+b and you get

y=-1/2x-4

4 0
3 years ago
How to solve this equation for the variable b a^2+b^2=c^2 ?
Nata [24]

Firstly, subtract a^2 on both sides: b^2=c^2-a^2

Next, we are going to be using the difference of squares, which is x^2-y^2=(x+y)(x-y) . Use this on the right side of the equation: b^2=(c+a)(c-a)

Lastly, square root both sides of the equation, and <u>your answer will be b=\sqrt{(c+a)(c-a)}</u>

5 0
2 years ago
2(4y - 5) &lt; - 2 please help
34kurt

Answer:

y  <  1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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