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JulsSmile [24]
3 years ago
8

Which expressions are equivalent to the given complex number? 45 + 2i A. (2 + 8i) + 2(9 + 6i)(1 - i) B. (9 + 4i) + 2(4 + 7i)(1 -

2i) C. (13 + 4i) + 2(7 + 2i)(2 - i) D. (2 + 8i) + (30 - 6i) E. (9 + 4i) + (36 - 2i) F. (13 + 4i) + (32 - 6i)
Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer:

The correct expression is (9 + 4i) + (36-2i)

Step-by-step explanation:

Here, we want to find the expression that is equal to the given polynomial out of the options

The expression that is equal to 45 + 2i will be

(9 + 4i) + (36-2i)

That will yield;

9 + 36 + 4i-2i

= 45 + 2i

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Answer:

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About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

Where <em>e</em> is Euler's number.

Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

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