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Elis [28]
3 years ago
13

I need help plz help me

Mathematics
2 answers:
Tresset [83]3 years ago
5 0

Answer:

26

Step-by-step explanation:

Because DAC is a straight line we can equate that:

4x - 8 + 34 + 76 - x = 180

3x + 102 = 180

3x = 78

x = 26

Olenka [21]3 years ago
4 0

Answer:

26°

Step-by-step explanation:

Angles on a straight line add up to 180

4x - 8 + 34 + 76 - x = 180

3x + 102 = 180

3x = 78

x = 26°

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1.01<0.99 true,4.5=4.50 true, 3.5<3.39 true?, lastly is 1.51>1.15 true?
kirza4 [7]
No, yes, no, yes

What part of comparing number values do you not understand? Most folks figure out enough about place value to be able to answer this by 3rd grade. If there's something about this question that really stumps you, please advise in the comments.
5 0
3 years ago
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
2 years ago
A television weighs 8.50 pounds. How many grams is this? (Hint: You need to
Elza [17]

Answer:

Hello

The answer is 3855'5

Step-by-step explanation:

At first change lbs to kg.

Then you'll change the kg to grkg×1000=gr

7 0
3 years ago
Which set of numbers best describes the possible values of x in the equation below?[x-1]=[x] all integer values of x all real nu
SCORPION-xisa [38]

[x] represents floor function also called as Greatest integer function.

Floor function is the function that takes as input a real number and gives as output the greatest integer less than or equal to.

like [1.5]=1

[0.7]=0

[-0.3]=-1

Now we have to find set of x-values which satisfies equation [x-1]=[x]

Due to -1 in [x-1], it always produces output value one less than value of [x]

for example when x=0.5 then [x]=[0.5]=0, [x-1]=[0.5-1]=[-0.5]=-1

when x=1.5 then [x]=[1.5]=1, [x-1]=[1.5-1]=[0.5]=0

when x=3 then [x]=[3]=3, [x-1]=[3-1]=[2]=2

From above results we can see that there is no value of x which satisfies the given equation [x-1]=[x]

Hence there is NO solution.

3 0
3 years ago
Read 2 more answers
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