5=−(−z+3)
Simplify:
5=−(−z+3)
5=z+−3(Distribute)
5=z−3
Flip the equation.
z−3=5
Add 3 to both sides.
z−3+3=5+3
z=8
Answer:
x = 12°
∠RST = 40°
∠STR = 100°
Step-by-step explanation:
Answer: 6.28 inches.
Step-by-step explanation:
Formula :
i) Area of sector :
, where x = central angle and r is radius
ii) Length of arc : ![l=\dfrac{x}{360}\times2\pi r](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7Bx%7D%7B360%7D%5Ctimes2%5Cpi%20r)
Given , r= 6 in.
A =
inches
Put these values in (i) , we get
![3\pi =\dfrac{x}{360}\times\pi (3)^2\\\\\Rightarrow\ 1=\dfrac{x}{120}\\\\\Rightarrow\ x=120^{\circ}](https://tex.z-dn.net/?f=3%5Cpi%20%3D%5Cdfrac%7Bx%7D%7B360%7D%5Ctimes%5Cpi%20%283%29%5E2%5C%5C%5C%5C%5CRightarrow%5C%201%3D%5Cdfrac%7Bx%7D%7B120%7D%5C%5C%5C%5C%5CRightarrow%5C%20x%3D120%5E%7B%5Ccirc%7D)
Now , put values of x and r in (ii) , we get
![l=\dfrac{120}{360}\times2\pi(3)\\\\\Rightarrow\ l=2\pi = 2(3.14)=6.28\text{ inches}](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7B120%7D%7B360%7D%5Ctimes2%5Cpi%283%29%5C%5C%5C%5C%5CRightarrow%5C%20l%3D2%5Cpi%20%3D%202%283.14%29%3D6.28%5Ctext%7B%20inches%7D)
Hence, the length of the arc is 6.28 inches.
I'm pretty sure the answer is pi/2. Just plugged it in my calculator and it said error.
Yes it's A and B