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NNADVOKAT [17]
3 years ago
14

What is the greatest integer solution of 5-3m<11

Mathematics
1 answer:
ki77a [65]3 years ago
8 0
The solution to your problem is  m>-2
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5k-2(3k + 4) = 5x + 4<br> help?
vazorg [7]
Use distributive property
5k - 6k -8 = 5x + 4
Combine like terms
-k - 8 = 5x + 4
add 8 to both sides
-k = 5x + 12
k = -5x- 12
4 0
3 years ago
Read 2 more answers
3/8, -2 , 34% , -4/9 from least to greatest
Whitepunk [10]
-2, -4/9 , 34%, 3/8. This is your answer
6 0
3 years ago
For what value of x would the expression below be undefined? 6x − 9 x − 5
Marina86 [1]
6x - 9x - 5 =

combine like terms

6 - 9 = - 3

- 3x - 5 = 

leave x by itself

- 3x - 5 = 
+3x
___
  0
       - 5 = 3x

solve for x (division)

        
- 5 = 3x
       ___
         3
-5/3 = x         OR         x = -5/3
3 0
3 years ago
In New York State's Quick Draw lottery, players choose between one and ten numbers that range from 1 1 to 80 . 80. A total of 20
amid [387]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
A softball pitcher has a 0.675 probability of throwing a strike for each pitch and a 0.325 probability of throwing a ball. If th
Dafna11 [192]

Answer:

The probability that exactly 19 of them are strikes is 0.1504

Step-by-step explanation:

The binomial probability parameters given are;

The probability that the pitcher throwing a strike, p = 0.675

The probability that the pitcher throwing a ball. q = 0.325

The binomial probability is given as follows;

p(x) = _{n}C_{x}\cdot p^{x}\cdot q^{1-x}

Where:

x = Required probability

Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;

The probability that exactly 19 of them are strikes is given as follows;

\binom{29}{19}(0.675)^{19}0.325^{10} = \frac{29!}{19!\times 10!}\times (0.675)^{19}\times 0.325^{10} = 0.1504

Hence the probability that exactly 19 of them are strikes = 0.1504

8 0
3 years ago
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