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tester [92]
3 years ago
7

Maria earned &10.50 per hour working at an ice cream shop. She earned $147 each week before taxes. Write and solve an equati

on to find the number of hours (h) she worked each week.
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0
She worked 13 hours a week i think
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Answer:

Step-by-step explanation:

Let the edge of the cube be a .

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\frac{da}{dt} = 2 cm/s

Volume V = a³

\frac{dV}{dt} = 3a^ 2\frac{da}{dt}

= 3a² x 2

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If a = 40 cm

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12 3/8 divided by 3/4
oksano4ka [1.4K]

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Step-by-step explanation:

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romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

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4 years ago
600,000 1/10 of what? Please help!!
igor_vitrenko [27]
600000 is 1/10 of "x", that means x = 10/10 or a whole, what is "x"?

\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
600000&\frac{1}{10}\\\\
x&\frac{10}{10}
\end{array}\implies \cfrac{600000}{x}=\cfrac{\frac{1}{10}}{\frac{10}{10}}\implies \cfrac{600000}{x}=\cfrac{1}{10}
\\\\\\
\cfrac{600000\cdot 10}{1}=x
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Jasmon spent half of her weekly
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Answer:

10

Step-by-step explanation:

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