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weeeeeb [17]
3 years ago
8

Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

Mathematics
2 answers:
sesenic [268]3 years ago
4 0
<span>4x^3 + x^2 – 8x – 2
= (</span>4x^3 + x^2) – (8x + 2)
= x^2 (4x + 1) - 2(4x + 1)
= (x^2 - 2)(4x +1) 

hope that helps
ivann1987 [24]3 years ago
4 0

Answer:

A) x2(4x + 1) – 2(4x + 1)

Step-by-step explanation:

Edg

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F left parenthesis x right parenthesis equals 9 x cubed plus 2 x squared minus 5 x plus 4 and g left parenthesis x right parenth
Jet001 [13]
The answer is 2x(2x²+x+1).

When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)

9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0

This gives us 
4x³+2x²+2x

Each of these is divisible by 2, and each has an x, so we factor those out:
2x(                        )

4x³/2x = 2x²:
2x(2x²                   )

2x²/2x=x:
2x(2x²+x               )

2x/2x = 1:
2x(2x²+x+1)
3 0
3 years ago
A computer randomly selects a number from the given set.
SSSSS [86.1K]

23 for 5=6

Step-by-step explanation:

7 0
3 years ago
Is this right or wrong? Put these numbers in order from the smallest to the biggest. -1/5, -2/3, 2, 4.
quester [9]

Answer:no the -2/3 should be before -1/5

Step-by-step explanation:

8 0
3 years ago
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The probability distribution of random variable, X, is defined as follows:
stealth61 [152]

Answer and Step-by-step explanation:

A) For the model to be a probability distribution, it has to follow two conditions:

1) The probability of each value of the discrete random variable is between, and included, 0 and 1:

2) The sum of all probabilities is 1;

In the table shown, the probabilities are from 0 to 0.3 - between 0 and 1;

Adding the probabilities: 0 + 0.3 + 0.1 + 0.3 + 0.3 = 1

Therefore, this model is a valid probability distribution model.

B) They are discrete because each value correspond to a finite number of possible values.

C) Expected value is calculated by

E(X) = \Sigma xP(x)

E(X) = 0.0 + 1*0.3 + 2*0.1 + 3*0.3 + 4*0.3

E(X) = 2.6

D) P(X=3) = P(3), which means probability of 3:

P(X=3) = 0.3

E) P(X<4): probabilities of values of X that are less than 4:

P(X<4) = P(0) + P(1) + P(2) + P(3)

P(X<4) = 0 + 0.3 + 0.1 + 0.3

P(X<4) = 0.7

F) P(X>0) = P(1) + P(2) + P(3) + P(4)

P(X>0) = 0.3 + 0.1 + 0.3 + 0.3

P(X>0) = 1

G) P(X=5) = P(5)

There is no probability of P(5) because the model doesn't "cover" that number.

H) P(X=0) = P(0)

P(X=0) = 0

I) The total area of any density curve is 1 because it represents all the possible values a variable can assume.

3 0
4 years ago
Go to CPSB.agilemind.com
schepotkina [342]

Answer:

False, it isn't right.

Step-by-step explanation:

5 0
3 years ago
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