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Lady_Fox [76]
4 years ago
7

Please help. I will give brainiest. Please.

Mathematics
1 answer:
andre [41]4 years ago
5 0
Quotient of Powers, Power of a Power. Power of a power for the |(-8)^4)|^-5 and quotient of powers for the division of powers. And I think negative exponents for after the division of the powers. 
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What type of angles are the 2 algebraic expressions in problem #17? Please help me!!
pashok25 [27]

Answer:

Alternate interior angles

Step-by-step explanation:

Hi there!

These two angles are alternate interior angles. Notice how they form a "Z" shape. We can use that feature to recognize these types of angles.

I hope this helps!

3 0
3 years ago
The radius of a sphere is 6 units. Find the volume of the sphere. Write your answer in terms of pi
lara [203]

Answer:

V = 288 pi

Step-by-step explanation:

V=4/3 pi r^3

r = 6                                  Substitute

V = 4/3 * pi * 6 * 6 * 6       Divide 3 into one of the sixs leaving 2

V = 4 pi * 2 * 6 * 6            Combine

V = 288 pi

7 0
3 years ago
A researcher studied the relationship between the number of times a certain speciesof cricket will chirp in one minute and the t
cricket20 [7]

Answer:

C. Actual temperature of 57.1°F when the cricket has chirped 116 times

Explanation:

The x-axis represents the number of chirps per minute.

The values on the y-axis represent the temperature (in °F).

Given the point (116, 57.1)

• The number of chirps per minute = 116

,

• Temperature = 57.1°F

Thus, the point (116, 57.1) represent an actual temperature of 57.1°F when the cricket has chirped 116 times.

4 0
1 year ago
The range of a projectile that is launched with an initial velocity v at an angle of a with the horizontal is given by R
lara31 [8.8K]

Answer:

\theta=30.285^{\circ}

Step-by-step explanation:

The range of a projectile is given by :

R=\dfrac{u^2\sin2\theta}{g}

Put R = 20 m, u = 15 m/s and finding the value of angle of projection

So,

R=\dfrac{u^2\sin2\theta}{g}\\\\\sin2\theta=\dfrac{Rg}{u^2}\\\\\sin2\theta=\dfrac{20\times 9.8}{15^2}\\\\\sin2\theta=0.871\\\\2\theta=\sin^{-1}(0.871)\\\\2\theta=60.57\\\\\theta=30.285^{\circ}

So, the required angle of projection is equal to 30.285^{\circ}.

3 0
3 years ago
-14x > -3 can someone help please
I am Lyosha [343]

Answer:

.

Step-by-step explanation:

8 0
3 years ago
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