There are 1 rectangle and 2 triangles.
The area of the rectangle is 5 x 7 =35
The are of the triangle is 7 x 2 = 14(1/2) = 7
There are 2 triangles, so 7 x 2 = 14
14 + 35 = 49
49 is your answer
hope this helps
Answer:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Step-by-step explanation:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Answer:
d. 6
Step-by-step explanation:
The product of lengths to the near and far intersection points is the same for both secants:
PB×PA = PD×PC
We can use this relation to solve for x, then use the value of x to find PD.
7×12 = (3x)(7x)
4 = x² . . . . . . . . . divide by 21
2 = x . . . . . . . . . . take the square root
__
PD = 3x = 3·2
PD = 6
the height of the house is 
.
<u>Step-by-step explanation:</u>
Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find What is the height of the house . Let's find out:
Let y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.
Distance of house from point A( initial point ) = x ft
Distance of house from point B( when she traveled 200 ft towards street = x-200 ft
Now , According to question these scenarios are of right angle triangle as
At point A
⇒ 
⇒ 
⇒ 
..................(1)
Also , At point B
⇒ 
⇒ 
..............(2)
Equating both equations:
⇒ 
⇒ 
⇒ 
⇒ 
Putting in we get:
⇒
⇒ 
⇒ 
Therefore , the height of the house is .
Answer:
wait so what is the numbers of distance they have swam?
Step-by-step explanation:
