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Nat2105 [25]
3 years ago
13

What is the quotient (x^3-3x^2+3x-2) divided by (x^2-x+1)

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0
If you do the long division you'll see that it is x - 2.
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Which representation does not show a proportional relationship between x and y?
nasty-shy [4]

Answer:

Table A

Step-by-step explanation:

looking at the two tables, we have the observations as follows;

For table B, if we divide x by y; we have a ratio of 2/3

This happens throughout the table

What this means is that x = 2/3 * y

But for table A, we notice a pattern for the first two lines

The pattern here is that x = 2y

But as we move to the next two rows, we notice this fails and thus, we fail to establish a pattern that works for all the rows;

Hence table B has a pattern for all its rows

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A triangle with two 8
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Answer:

One unique triangle

Step-by-step explanation:

3 0
2 years ago
Erica watched 2.7 miles to and from work every day for an entire year how many miles did he walk
Len [333]
2.7 • 2 because it’s twice a day. He’s waking 5.4 miles daily, 5.4 • 360 = 1,944 miles yearly.
7 0
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Which statement is true about PQ in relation to the circumscribed circle ?
tatyana61 [14]

check the picture below.

5 0
3 years ago
Read 2 more answers
Can anyone please help me in this
Alik [6]

These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.

We know that we can solve one variable equation easily. For example...

x+1=2

x=1 obviously

Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.

So what can we do? We have to make a two variable equation into a one variable equation.

There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.

x+y=2

2y-y=1

3)  

-3x-5y=-7 -----> -12x-20y=-28

-4x-3y=-2 ------> -12x-9y=-6

 -12x-20y=-28

-(-12x-9y=-6)

---------------------

-11y=-22

y=2

-3x-5(2)=-7

-3x=3

x=-1

4) 8x+4y=12 ---> 24x+12y=36

7x+3y=10 ---> 28x+12y=40

 28x+12y=40

-(24x+12y=36)

---------------------

4x=4

x=1

8(1)+4y=12

4y=4

y=1

5) 4x+3y=-7

-2x-5y=7 ----> -4x-10y=14

    4x+3y=-7

+(-4x-10y=14)

-------------------

-7y=7

y=-1

4x+3(-1)=-7

4x=-4

x=-1

6) 8x-3y=-9 ---> 32x-12y=-36

5x+4y=12 ---> 15x+12y=36

 32x-12y=-36

+(15x+12y=36)

--------------------

47x=0

x=0

8(0)-3y=-9

-3y=-9

y=3

7)-3x+5y=-2

2x-2y=1 ---> x-y=1/2 ----> x=y+1/2

-3(y+1/2)+5y=-2

-3y-1.5+5y=-2

2y=-0.5

y=0.25

2x-2(0.25)=1

2x=1.5

x=0.75

4 0
3 years ago
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