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Svetradugi [14.3K]
3 years ago
7

What is the value of y? Enter your answer in the box. y =

Mathematics
1 answer:
Vlad [161]3 years ago
8 0
79+37=116
180-116=64
Answer- 64
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A city has 3 new houses for every 9 old houses. If there are 21 new houses in the city, how many old houses are there?
kipiarov [429]
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
5 0
3 years ago
A cylinder has radius 2.5 cm and lateral area 20 pi cm^2. What is the surface area of the cylinder in terms of pi?
Novosadov [1.4K]
This is the concept of areas of solid materials; the surface area of the cylinder whose radius is 2.5 cm and lateral area is 20 pi cm^2 will be: Surface area of cylinder is given by:
SA=(area of cyclic sides)+(lateral area)
SA=2πr^2+πrl
Area of the cyclic sides will be:
Area=2πr^2
=2*π*2.5^2
=12.5π cm^2
The lateral area is given by:
Area=20π cm^2
Therefore the surface area of cylinder will be:
SA=(12.5π+20π) cm^2
SA=32.5π cm^2
The answer is 32.5π cm^2

4 0
3 years ago
The sum of two integers is 121. The larger integer is 7 more than twice the smaller integer. Find the two integers.
iren [92.7K]
X + (2x + 7) = 121 : Write the expression.
3x + 7 = 121 : Combine like terms.
3x + 7 - 7 = 121 - 7 : Isolate x.
3x = 114 : Combined like terms.
3x / 3 = 114 / 3 : Find the value of x.
x = 38 : This is the smaller integer.
(2x + 7) = (2(38) + 7) = 76 + 7 = 83. : Find the value of the larger number by plugging in the value of x to the larger number's quantity.
The larger number is 83, and the smaller number is 38.
5 0
3 years ago
A right triangle has a perimeter of 24 cm and a hypotenuse of 10 cm. Find the length of the other two sides.
jekas [21]

Answer:

One of the sides is 6 cm and the other is 8 cm

Step-by-step explanation:

Let's call the unknown sides a and b. From the perimeter information (24 cm) we have:

a + b + hypotenuse = 24

a + b + 10 = 24

a + b = 14

b = 14 - a

So now we can right the Pythagorean theorem as follows:

a^2 + b^2 = hypotenuse^2\\a^2 + (14-a)^2=10^2\\a^2+ 14^2-28\,a+a^2=100\\2\,a^2-28\,a +96=0\\2\,(a^2-14\,a+48)=0\\2\,(a^2-6\,a-8\,a+48)=0\\2(a\,(a-6)-8\,(a-6))=0\\2\,(a-6)\,(a-8)=0

and from this expression in factor form to be zero a must be 6 or a must be 8.

Therefore the solutions are a = 6 (and therefore b = 14 - 6 = 8)

or a = 8 (and therefore b = 14 - 8 = 6)

7 0
3 years ago
Read 2 more answers
I need help with this
elena55 [62]
The answer to this is choice D
4 0
3 years ago
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