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dem82 [27]
2 years ago
10

Will give Brainliest

Mathematics
1 answer:
ch4aika [34]2 years ago
7 0

Answer:

  • B. Quadrilateral PQRS is a trapezoid, because there is one pair of equal slopes, and thus one pair of parallel sides.

Step-by-step explanation:

<u>Given:</u>

  • The slopes of the sides of quadrilateral PQRS are −23, 78, −23, and 1112.

As we see two of the slopes are same, indicating a pair of parallel sides.

The other two slopes are different, so there is only one pair of parallel sides.

This is a definition of a trapezoid.

Correct choice is B

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Step-by-step explanation:

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Comparing this to equation of a straight line, y=mx+c

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slope (m) = 0.719

And intercept (c) on y axis is 1.507

Then, the x axis is lcavol

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Check attachment for the preview.

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2 years ago
Solve for x in the following equation: 4(-5x-6) = 4(9x+4)
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2 years ago
A variable that is manipulated by an experimenter to explore its relationship to other variables is a(n) _____ variable.
LuckyWell [14K]

Answer:

Independent variable

Step-by-step explanation:

Independent variable :

An independent variable is a variable that speaks to an amount that is being controlled in a trial. A needy variable speaks to an amount whose worth relies upon those controls.  

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3 years ago
A construction crew is lengthening a road. Let L be the total length of the road (in miles). Let D be the number of days the cre
djverab [1.8K]

Answer:

Set of Values for Domain = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80}

Set of Values for Range = {402, 404, 406, 408, 410, 412, 414, 416, 418, 420, 422, 424, 426, 428, 430, 432, 434, 436, 438, 440, 442, 444, 446, 448, 450, 452, 454, 456, 458, 460, 462, 464, 466, 468, 470, 472, 474, 476, 478, 480, 482, 484, 486, 488, 490, 492, 494, 496, 498, 500, 502, 504, 506, 508, 510, 512, 514, 516, 518, 520, 522, 524, 526, 528, 530, 532, 534, 536, 538, 540 542, 544, 546, 548 550, 552, 554, 556, 558, 560}.

Step-by-step explanation:

Solution...

Assume that there is a link for the road between your house and the market the road maintenance team is meant to repair the road.

now the system of work is that the length of the road they will work upon is equal to 2 times the amount of days + 400.

This is to say that originally there is 400 miles of the road, and once they work in a day they add 2 more miles to the original 400. if they work in 2 days they add 4 more miles to the original 400. If they work in 3 days they add 6 more miles to the original 400.

So L = 2(D) + 400.

Answer 1.

description of the values in both the domain and range of a function.

the domain is the set of all values for which the function is defined.

this means that the domain is all numbers between 0 to 80.

Why do we begin from 0, because when you put 0 into the equation you have, L = 2(0) + 400, and this is equal to 2 x 0 + 400 or 400 + 0 (since all numbers multiplied by 0 gives 0).

Why is 80 the maximum, this is because they work for at most 80 days.

So the domain is

D = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80}

And the range is the set of all values that L (which is the function) takes, to get this you have to calculate the days from day 0 to day 80.

The range for the function is...

L = {402, 404, 406, 408, 410, 412, 414, 416, 418, 420, 422, 424, 426, 428, 430, 432, 434, 436, 438, 440, 442, 444, 446, 448, 450, 452, 454, 456, 458, 460, 462, 464, 466, 468, 470, 472, 474, 476, 478, 480, 482, 484, 486, 488, 490, 492, 494, 496, 498, 500, 502, 504, 506, 508, 510, 512, 514, 516, 518, 520, 522, 524, 526, 528, 530, 532, 534, 536, 538, 540 542, 544, 546, 548 550, 552, 554, 556, 558, 560}.

So how did we get all these. Using the figures registered as D to get the L.

Before solving, remember that, (HD is H•D or H × D,

2D is 2•D or 2 × D,

29F is 29•F or 29 × F... When numbers are used to multiply letters which stand as a varying value like X, Y, D etc, then they are written as 2x or 2•x or 2(x). They all mean multiply 2 by x)

So, i.e.

L = 2(D) + 400.

When it's day 1, D is 1

L = 2(1) + 400 which equals 2 + 400 = 402. So for 1 day, the crew has worked 402 miles.

On Day 2, D is 2

L = 2(2) + 400 which equals 4 + 400 = 404. So for 2 days, the crew has worked 404 miles.

On Day 3, D is 3

L = 2(3) + 400 which equals 6 + 400 = 406. So for 3 days, the crew has worked 406 miles.

On Day 4, D is 4

L = 2(4) + 400 which equals 8 + 400 = 408. So for 4 days, the crew has worked 408 miles.

On Day 5, D is 5

L = 2(5) + 400 which equals 10 + 400 = 410. So for 5 days, the crew has worked 410 miles.

On Day 6, D is 6

L = 2(6) + 400 which equals 12 + 400 = 412. So for 6 days, the crew has worked 412 miles.

...

...

...

For 7 days, the crew has worked 414 miles.

For 8 days, the crew has worked 416 miles.

For 9 days, the crew has worked 418 miles.

For 10 days, the crew has worked 420 miles.

For 20 days, the crew has worked 440 miles.

For 30 days, the crew has worked 460 miles.

For 40 days, the crew has worked 480 miles.

For 50 days, the crew has worked 500 miles.

For 60 days, the crew has worked 520 miles.

For 70 days, the crew has worked 540 miles.

For 75 days, the crew has worked 550 miles.

...

...

...

On Day 79, D is 79

L = 2(79) + 400 which equals 158 + 400 = 558. So for 79 days, the crew has worked 558 miles..

On Day 80, D is 80

L = 2(80) + 400 which equals 160 + 400 = 560. So for 80 days, the crew has worked 560 miles.

That is how the domain and range is determined.

6 0
3 years ago
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