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vagabundo [1.1K]
3 years ago
7

Find the percentage of students that scored higher than 95.5. Round your answer to the nearest percent.

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

Answer:

\% Change = \frac{9}{64} *100 = 14.0625\% \approx 14\%

So then we have approximately 14% of the values higher than 95.5

Step-by-step explanation:

For this case we assume that the info is given on the figure attached.

From this figure we have the following frequencies for each class

Class                  Frequency

___________________________

70.5-75.5                13

75.5-80.5                7

80.5-85.5                6

85.5-90.5                10

90.5-95.5                19

95.5-100.5               9

____________________________

Total                        64

So we have a total of 64 values and we want to find the percentage of students that scored higher than 95.5 so we can use the formula of relative change and we got:

\% Change = \frac{9}{64} *100 = 14.0625\% \approx 14\%

So then we have approximately 14% of the values higher than 95.5

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bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

6+25/100 =6+0.25=6.25 cm

Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

circumference= pie(d) = pie(6)= 3.14times6= 18.84

Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

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Step-by-step explanation:

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