All categories

3 years ago

Find the percentage of students that scored higher than 95.5. Round your answer to the nearest percent.

Mathematics

1 answer:

My name is Ann [436]3 years ago

6 0

Answer:

$\% Change = \frac{9}{64} *100 = 14.0625\% \approx 14\%$

So then we have approximately 14% of the values higher than 95.5

Step-by-step explanation:

For this case we assume that the info is given on the figure attached.

From this figure we have the following frequencies for each class

Class Frequency

___________________________

70.5-75.5 13

75.5-80.5 7

80.5-85.5 6

85.5-90.5 10

90.5-95.5 19

95.5-100.5 9

____________________________

Total 64

So we have a total of 64 values and we want to find the percentage of students that scored higher than 95.5 so we can use the formula of relative change and we got:

$\% Change = \frac{9}{64} *100 = 14.0625\% \approx 14\%$

So then we have approximately 14% of the values higher than 95.5

You might be interested in

A cookie factory uses 1/2 of a barrel of oatmeal in each batch of cookies. The factory used 3 1/2 barrels of oatmeal yesterday.

Helen [10]

First, to make this a bit easier, we can turn the fractions into decimals.

1/2 = 0.5 , 3 1/2 = 3.5

Divide 3.5 by 0.5.

3.5 ÷ 0.5 = 7

<h2>Answer: </h2>

<u>The factory made </u><u>7 batches of cookies</u><u>.</u>

7 0

2 years ago

Algebra help plss222

nadya68 [22]

Answer:

I'm a little unsure but I think it should be y = $-\frac{1}{9}$

3 0

2 years ago

Read 2 more answers

Mary and Jane both took PSY230 last semester but they were in two different sections taught by different professors. Mary's clas

Greeley [361]

Answer:

Due to the higher z-score, Jane did better in class.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Whoever's grade had the better z-score did better in class.

Mary's:

Mean of 85, standard deviation of 5, grade of 88. This means that $\mu = 85, \sigma = 5, X = 88$ . So