Question

A square and a rectangle have the same perimeter. The square has a side length of 8x units. The rectangle has a length of (5x+8) units and a width of 14 units. What will the perimeter of both the rectangle and the square

Answer 1

Answer:

The perimeter of both figures is equal to $64\ units$

Step-by-step explanation:

step 1

we know that

The perimeter of a square is equal to

$P=4b$

where

b is the side length of the square

we have

$b=8x\ units$

substitute

$P=4(8x)=32x\ units$

step 2

we know that

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$L=(5x+8)\ units$

$W=(14)\ units$

substitute

$P=2(5x+8+14)=10x+44\ units$

step 3

Equate both perimeters and solve for x

$10x+44=32x$

$32x-10x=44$

$22x=44$

$x=2\ units$

step 4

Find the perimeter of both

square

$P=32x=32(2)=64\ units$

rectangle

$P=10x+44=10(2)+44=64\ units$