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Svetlanka [38]
3 years ago
14

Which table represents a quadratic

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
B - the second one i’m pretty sure
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A first number plus a second number is 10. Twice the first number plus the second totals 26.
MakcuM [25]
1st number = x
2nd number = y

2x + y = 26
                    -
  x + y = 10

x = 16

26 - (2 x 16) = -6

10 - 16 = -6


Number 1 is 16
Number 2 is -6


3 0
3 years ago
The sum of two numbers is -17 and their difference is 41 what are the two numbers?
liberstina [14]

Answer: the two numbers are 7 and -27

Step-by-step explanation:

Let the two numbers be a and b

From the question,

a + b = -27.......eqn 1

a - b = 41............eqn 2

Sum the two equations

2a = 14

Divide both sides by 2

a = 14/2; a = 7

Substitute a = 7 into equation 2

a - b = 41

7 - b = 41

Make b the subject of the equation

-b = 41 -7

-b = 34

b = -34

Check:

a + b = -27, slot the values of a and b

7 + (-34) = -27

7- 34 = -27

I hope this is clear, please mark as brainliest answer

7 0
3 years ago
3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third
den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

=  > 2x + 3x + 6 = 2x + 8 + 55

Eliminating 2x from both the sides,

=  > 3x + 6 = 63

=  > 3x = 63 - 6 = 57

=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

3 0
2 years ago
Please help me asap!!
Alika [10]

Answer:

35

Step-by-step explanation:

what I did was add GJ together and imaged it in my head to see if it would fit... I'm not sure tho

3 0
3 years ago
Read 2 more answers
What is the solution set for
lana [24]
It’s s=-2 and s=2 because the absolute value makes both of the numbers be positive so either way it’s going to be 2+4=6
5 0
2 years ago
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