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lisov135 [29]
3 years ago
15

GIVING BRAINLIEST PLS HELP

Mathematics
1 answer:
AveGali [126]3 years ago
5 0

Answer:

f(x) = x

Step-by-step explanation:

note : slope is positive 1, so the x term must be positive

also note the graph intersects the curve at y = 0, which means that they y-intercept is zero .

if we substitute this into the general equation for a line

y = mx + b, where m = +1 and b = 0,

we get y = x

or f(x) = x (in function form)

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Darya [45]
Based on the equation, the coordinate point is (-4, 2). It is -4 because in the original equation, it's -x_{1}, but because it's positive, that must mean it was originally a negative. Why? Because a negative times an negative equals a positive.

Now, let's convert this to Slope-Intercept Form.

y - 2 = 2/3(x + 4)
y - 2 = 2/3x + 8/3
Add 2 to both sides.
y = 2/3x + 14/3

The slope of the line is 2/3 and the original point was (-4, 2).

6 0
3 years ago
(6,-2) and a slope of 4/3 in point slope form
Rufina [12.5K]

Answer: y=4/3x-10

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Hope this helps you out! ☺

7 0
3 years ago
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marshall27 [118]

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Step-by-step explanation:

3 0
3 years ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
Which of the following is not a way to represent the solution of the inequality 2(x − 1) greater than or equal to −12?
maxonik [38]
First you need to simplify the left side of the equation to get 2x-2 \geq -12
Then you add by two on both sides to get 2x \geq -10
Finally you divide by 2 on both sides to get x \geq -5
6 0
3 years ago
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