The data collected from the actual game experiment is:
Win: 8 times
Lose: 40 times
Total trials: 48 times
Therefore, the probability that you will win when you play this game is:
WIN = 8/48
= 1/6 or 0.1667 = 16.67% chance of winning
LOSE = 40/48
= 5/6 or 0.8333 = 83.33% chance of losing.
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This is not a valid question and, therefore, cannot be answered. (Reason: No graph is attached.) Try revising it or giving more information. Hope this helps! ❤️
Step-by-step explanation:
if f(1)=-4, then adding 5 would give you 1, again would give you 6, again would give 11. Therefore, your first four terms are -4,1,6,11.
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
100,000 + 75,000 = 175,000. To get the answer, you add the two.