35 :) If you change the percent into a decimal (0.70) and multiply that by 50, you will get the answer!
Answer:
The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.
The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.
The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.
Answer:
Step-by-step explanation:
A)Initial amount deposited into the account is $6500 This means that the principal is P, so
P = 500
It was compounded daily. This means that it was compounded 360 times in a year. So
n = 360
The rate at which the principal was compounded is 3%. So
r = 3/100 = 0.03
It was compounded for 5 years. So
t = 5
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. Therefore
A = 6500 (1+0.03/360)^360×5
A = 6500 (1+0.00008333333)^360×5
A = 6500 (1.00008333333)^1800
A = $7551.70
B) The interest earned is Total amount earned - principal. It becomes
7551.7 - 6500 = $1051.7
A a dilation and reflection
dilation will make bigger or smaller therefore it cannot be congruent
