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3 years ago

14

I Having trouble with this please help

2 answers:

Schach [20]3 years ago

5 0

The line touching the point (0,3) goes to the equation y= 2x + 3 because + 3 represents the y-intercept. The line touching (0,-2) goes to the equation y = 2x - 2 because - 2 represents the y-intercept as well.

dalvyx [7]3 years ago

3 0

The upper line has the y-intercept +3; the lower line has the y-intercept -2. This should make it simple for you to identify which graph matches which equation.

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Bases are squares with sides that measure 27 inches. The height is 12 inches.

Elan Coil [88]

Answer:

Part 1) $V=8,748\ in^3$

Part 2) $SA=2,754\ in^2$

Step-by-step explanation:

<u><em>The correct question is</em></u>

Find the volume and the surface area of a rectangular prism. Bases are squares with sides that measure 27 inches. The height is 12 inches.

Part 1) Find the volume of the prism

The volume of the prism is equal to

$V=Bh$

where

B is the area of the base

h is the height of the prism

<em>Find the area of the base B</em>

$B=27^2=729\ in^2$ ---> the base is a square

we have

$h=12\ in$

substitute

$V=(729)(12)=8,748\ in^3$

Part 2) Find the surface area of the prism

The surface area of the prism is equal to

$SA=2B+Ph$

where

B is the area of the base

P is the perimeter of the base

h is the height of the prism

<em>Find the perimeter of the base P</em>

<em></em> $P=4(27)=108\ in$ <em></em>

substitute the values in the formula

$SA=2(729)+108(12)=2,754\ in^2$

3 0

3 years ago

At Sanger’s auto garage, three out of every five cars brought in for service need an oil change. Of the cars that need an oil ch

Alina [70]

Answer:

The probability that a car that comes into the garage needs both an oil change and a tire rotation is $\frac{12}{35}$ .

Step-by-step explanation:

The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

Denote the events as follows:

<em>X</em> = cars brought in for service need an oil change

<em>Y</em> = cars brought in for service need a tire rotation

The information provided is:

$P(X)=\frac{3}{5}$

$P(Y|X)=\frac{4}{7}$

Compute the value of P (X ∩ Y) as follows:

$P(Y|X)=\frac{P(X\cap Y)}{P(X)}$

$\frac{4}{7}=\frac{P(X\cap Y)}{3/5}$

$P(X\cap Y)=\frac{4}{7}\times \frac{3}{5}$

$=\frac{12}{35}$

Thus, the probability that a car that comes into the garage needs both an oil change and a tire rotation is $\frac{12}{35}$ .

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2 years ago

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Answer:

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2 years ago

Solve for x in a right triangle (show work)

Semmy [17]

Answer:

x = 89. 98⁰

Step-by-step explanation:

tan(x) = 29/ 14

x = tan-¹ (29/14)

x = 89. 98⁰

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2 years ago

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DENIUS [597]

Answer:

b

Step-by-step explanation:

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