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My name is Ann [436]
3 years ago
8

A chemist is using 356 milliliters of a solution of acid and water. If 14.1% of the solution is acid, how many milliliters of ac

id are there? Round your answer to the nearest tenth.
Mathematics
1 answer:
likoan [24]3 years ago
4 0
50.2 milliliters of acid
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Only male crickets chirp. They chirp at different rates depending on their species and the temperature of their environment. Sup
bezimeni [28]

Answer:

4920

7084800

2585952000

Step-by-step explanation:

82 chirps = 1 minute

We have 60 minutes in one hour, so 82 x 60 =4920 chirps in one hour

In 24 hours we have 60x24 = 1440 minutes and in one minutes we have 4920 chirps,

Therefore 4920 x 1440 mins =7084800 chirps in one day .

There are 365 days in a year and in one day the cricket chirps 7084800, so 365 days x 7084800 = 258595200 chirps in a year

6 0
3 years ago
(x+3y=6<br> 16x + 18y = 36
jonny [76]

Answer:

X = 0 , y=2

Step-by-step explanation:

Check attachment

7 0
3 years ago
Write an equation or system of equations to solve the problem below.
VashaNatasha [74]

Equations:

2x+105=-3x+130

<em>subtract</em><em> </em><em>2x</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em>

<em>105</em><em>=</em><em> </em><em>-5x</em><em>+</em><em>130</em>

<em>Subtract</em><em> </em><em>130</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>

<em>-5x</em><em>=</em><em> </em><em>-25</em>

<em>isolate</em><em> </em><em>the</em><em> </em><em>variable</em>

<em>x</em><em>=</em><em>5</em><em> </em>

<u>Plug</u><u> </u><u>back</u><u> </u><u>in</u>

<u>2</u><u>(</u><u>5</u><u>)</u><u>+</u><u>105</u><u>=</u><u> </u><u>-3</u><u>(</u><u>5</u><u>)</u><u>+</u><u>130</u>

<u>115</u><u>=</u><u> </u><u> </u><u>115</u>

5 0
3 years ago
PLEASE HELP ASAP I WILL GIVE 25 POINTS AND BRAINLIEST FOR JUST THIS ONE QUESTION FOR THE CORRECT ANSWER
ohaa [14]

Answer:

A

Step-by-step explanation:

2x is the parent function and -6 is the y intercept

8 0
3 years ago
Read 2 more answers
Probability of a standard six side dice landing on a four in the first three rolls?
Illusion [34]

Answer:

91/216

Step-by-step explanation:

The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.

P(at least one 4) = 1 − P(no 4s)

P(at least one 4) = 1 − (5/6)³

P(at least one 4) = 91/216

Alternatively, you can calculate it this way.

The probability of getting a 4 on the first roll is 1/6.

The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.

The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.

The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.

6 0
2 years ago
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