Ask question

Ask question

All categories

3 years ago

13

12a^-8b^3/3a^-4b^6 what is the answer

1 answer:

wel3 years ago

3 0

(12a^-8b^3/3a^-4) (b^6)

= 4b^9/a^12

hope this helps.

You might be interested in

10. What is the difference between: BD and BD ? Justify your answer.

exis [7]

Answer:

not in the same angles?

Step-by-step explanation:

3 0

4 years ago

someone help on the "how did basil know" part before i sue and quit school. i just wanna sleep it's 12 am.

PtichkaEL [24]

Well, the last digit in the product will only come from the last digits of the numbers that you're multiplying together. So for 0.303 & 4.48, that last digits are 3 & 8 so that last digit in the product would come from
$3 \times 8 = 24$
So 4. There are only two options that end in 4, 1.35744 & 0.13574. You can by the magnitude of the numbers that it isn't as small as 0.13574 so the answer must be 1.35744.

4 0

4 years ago

A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

$\therefore V=36\pi h_1$

Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

Putting $\frac{dh_1}{dt}=4$

$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

7 0

4 years ago

Jeremy's father drives him to school in rush hour traffic in 20 minutes. One day there is no traffic, so his father can drive hi

umka21 [38]

Answer:

Step-by-step explanation:

18/60-12/60= 4 miles

just my guess

6 0

4 years ago

Find a positive number that equals 72 when added to it square

nordsb [41]

That would be 8

8 square is 64 + 8 is 72 :)

7 0

3 years ago