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3 years ago

12a^-8b^3/3a^-4b^6 what is the answer

Mathematics

1 answer:

wel3 years ago

3 0

(12a^-8b^3/3a^-4) (b^6)

= 4b^9/a^12

hope this helps.

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Is the given answer a reasonable solution to the problem ? <br><br> 7.92 • 10.21= 88.8632

Alexus [3.1K]

7.92 is less than 8
10.21 is less than 11
8*11=88
the answer is less than 88.
the answer seems to be unreasonable to me it's too high

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3 years ago

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vovikov84 [41]

Answer:

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3 years ago

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Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

$sin(A)=\frac{BC}{AB}$

substitute the values

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Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

3 years ago

at the aquarium the dolphins are fed 7 buckets of fish each day the penguins are fed 1/2 as much as the dolphins how many bucket

DanielleElmas [232]

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Answer:

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Step-by-step explanation:

Already,it has been stated and proved that two angles (<ABC and <CAB) and an included side (AB) in ∆ABC are congruent to corresponding two angles (<ABD and <DAB) and an included side (AB) in ∆ABD.

Therefore, based on the ASA Congruence Theorem, ∆ABC is congruent to ∆ABD.

The missing reason is "ASA Congruence Theorem"

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3 years ago