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k0ka [10]
3 years ago
12

Today, a factory inspector found flaws in 2 out of 16 wooden boxes. If the inspector checks 24 boxes tomorrow, predict how many

of the boxes will be flawed.
Mathematics
2 answers:
Mumz [18]3 years ago
7 0

Answer:

3

Step-by-step explanation:

The assumed frequency of defects is 2/16.

When we apply this rate to 24, (2/16)*24, we get 3.

Therefore, we can assume around 3 defective boxes tomorrow.

____ [38]3 years ago
7 0

Answer:

3

Step-by-step explanation:

The assumed frequency of defects is 2/16.

When we apply this rate to 24, (2/16)*24, we get 3.

Therefore, we can assume around 3 defective boxes tomorrow.

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5/6k+2/3=4/3 <br> What is K? <br> I don't understand how to do these
Drupady [299]
First, subtract 2/3 from both sides and you get \frac{5}{6} k =  \frac{2}{3}
Then multiply both sides by 6/5 and you get k =  \frac{4}{5}
8 0
3 years ago
Explain the mistake made
olga55 [171]
In the second step you should have subtracted the 2x to move it to the other or side of the equals sign
8 0
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Which number line shows the estimate of 22 in the correct interval of integers?​
Marta_Voda [28]

Answer:

the answer is B

Step-by-step explanation:

Just estimate ex: 5 x 5 would be 25, so sqrt 22 would be just before the 5.

5 0
3 years ago
Read 2 more answers
Help meeeeeee its all due toad​
solniwko [45]

Well, the answer would bee 1/10 for a simple reason: the 3 in 7.315 is in the tenth's spot while the 3 in 893.5 is in the ones. a one spot different that can be proven with logic.

4 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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