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SVETLANKA909090 [29]
4 years ago
8

Store A has a promotion. If you buy three shirts, you get 25% off the total price of the three shirts. Store B has the same shir

ts on sale with the promotion that if you buy three shirts, you get the third shirt at a 50% discount. Store C has the same shirts on sale with a 10% discount. Assuming the three stores have the shirts priced equally before any promotion or sale and assuming you want to buy three shirts, which store�s promotion or sale gives you the better deal?
Mathematics
2 answers:
leva [86]4 years ago
8 0
Store A has the best deal.
Lets say shirts are $11 a piece. If you buy 3 that is $33. If you take 25% off, you save $8.25. B only saves $5.50 and C only saves $3.30
julsineya [31]4 years ago
5 0
So we are assuming that the three shirts have equal price. Let the price of one shirt be a.

In store A:

the cost is (a+a+a) -(25/100)a=3a-0.25a=2.75a

In store B: 

the cost is : a+a+50/100 a =a+a+0.5a=2.5a


In store C:

the cost is
[a-(10/100)a]+[a-(10/100)a]+[a-(10/100)a]=[a-0.1a]+[a-0.1a]+[a-0.1a]
=0.9a+0.9a+0.9a= 2.7a


thus the cost of buying the shirts from stores A, B and C is: 

2.75a, 2.5 a and 2.7 a respectively.

the best deal, is buying from store B, where the cost is the lowest: 2.5a.

Answer: store B




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Eggs sell for $1.09 per dozen at the local supermarket. If the supermarket pays $8.00 dollars her case that consist of 12 dozen
WARRIOR [948]

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B. $5.08

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3 0
4 years ago
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From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
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