Tenth blocks ones blocks
l l l l l l l o o
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>
<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>
<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>
<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>
<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
Answer:
it would be 1 million, ( 1,000,000 )
Step-by-step explanation:
1.) look to the right of the nine , (7)
2.) 7 is greater than five therefore rounding it up to 1,000,000
Area for a circle is
. We will fill in each area and then solve for the radius.
and
. ∴
and r = 13. For b,
and
.
, ∴ r = 17. For c,
, and
. ∴,
and r = 11. For d,
, and
. ∴,
so r = 25. And there you have it!
The correct answer would be 3
