Answer:
B. Find the area of the triangle PQR.
Answer:
x=103/265 y=18/53
Step-by-step explanation:
5x -9y=1-----------(i)
-7x+2y=-5-----------(ii)
Multiplying eq 1 with 7 gives
35x-63y=7---------eq(iii)
Multiplying eq 2 with 5 gives
-35x+10y=-25--------eq(iv)
adding eq 3 qnd eq 4
35x-63y-35x+10y=7-25
-53y=-18
y=18/53--------eq5
Putting the value of y from eq 5 in eq 1
5x-9(18/53)=-5
5x- 162/53=-5
5x=-5 +162/53
5x= -265+162/53
5x=103/53
x=103/265
Answer:
Exercise 1 : a. 4 ; b. -4
Exercise 2 : a. +7 positive/right ; b. -7 ; c. -7 negative/left
Step-by-step explanation:
The magnification is 0.54
Given,
The distance between object and concave lens, u = -21 cm
Focal length of the concave lens, f = -25 cm
Let m be the magnification.
m = v/u
Here v is the position of image.
We have to find v first.
By using lens equation we can determine v.
That is,
1/f = 1/v – 1/u
So,
- (1/25) = 1/v – (-1/21)
- (1/25) = 1/v + 1/21
1/v = - (1/25) – 1/21
1/v = (-25 – 21) / (21 x 25)
1/v = - (46/525)
Therefore v = - (525/46)
v = -11.41 cm
Now we have to find magnification, m.
m = v/u
= (-11.41) / (-21)
= 0.54
Here magnification is 0.54
Learn more about concave lens here: brainly.com/question/12944945
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