The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
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<span>(2, 4) and (−8, 84)
see the graph</span>
The decay factor of the exponential function given in the table is of
.
<h3>What is an exponential function?</h3>
A decaying exponential function is modeled by:

In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem, we have that when x increases by 1, y decreases by a factor of 3, hence the decay rate r is found as follows:



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8 and 24 let me know if this helps
Answer:
−8y2+9x+4y+11
Step-by-step explanation: