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Elis [28]
4 years ago
5

I GIVE FIVE STARS AND THANKS look at the screenshot--help??

Mathematics
2 answers:
Advocard [28]4 years ago
5 0
There isn't a screenshot, I cannot help you.
Delvig [45]4 years ago
4 0
Yeah same here and how did u not get screenshot
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Please answer <br> 3(x-1)=5x+3-2x
Setler [38]
Answer: there are no solutions



Step by step: Step 1: Simplify both sides of the equation.
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Step 2: Subtract 3x from both sides.
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6
6 0
3 years ago
Read 2 more answers
Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​
ElenaW [278]

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

8 0
3 years ago
It takes the teacher 39 minutes to grade 3 book reports. At this rate, how long will it take the teacher to grade 120 book repor
zzz [600]

it will take 1560 minutes

7 0
3 years ago
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A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
What is 0.0000981 in scientific notation?
tatiyna
9.81 or 98.1 pretty sure it's the first one

3 0
3 years ago
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