This is the function that models a boulder being pushed of a cliff. Find the height after 1.5 seconds.
1 answer:
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The graph starts at around x = 0. At x = 0, the graph's y-value is 2. There are no x-values that are less than 0.
The graph crosses the following points: (1,1); (4,0); (9, -1)
The distance between each y-value is exponentially increasing, as the slope of the graph is slowly decreasing as x approaches infinity.
Based on this information, we can say that this graph is a transformation of the base function, y = √x
To determine the transformations made, we need to compare the graph to the original base function (attached below).
The basic function starts at 0, and has a positive slope. It reaches the points (1,1); (4,2); and (9,3).
The graph in the question shows the function start at 2, and the negative slope reaching the points mentioned earlier in the answer.
Based on this information, we can conclude that y = -√x + 2.
The graph crosses the following points: (1,1); (4,0); (9, -1)
The distance between each y-value is exponentially increasing, as the slope of the graph is slowly decreasing as x approaches infinity.
Based on this information, we can say that this graph is a transformation of the base function, y = √x
To determine the transformations made, we need to compare the graph to the original base function (attached below).
The basic function starts at 0, and has a positive slope. It reaches the points (1,1); (4,2); and (9,3).
The graph in the question shows the function start at 2, and the negative slope reaching the points mentioned earlier in the answer.
Based on this information, we can conclude that y = -√x + 2.
Answer:
a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3
and V(0) = 900
where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to . Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.
(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.
Here again appears a constant B for the "proportional" part. And i wrote the velocity as "the rate of change of the position with respect to te time".