A cube that has a side lengths measuring 9 inches. (Find the area)

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Hey there,

Answer:

Area = L x B x H
= 9 x 9 x 9
= 729 inches ^ 3

Hope this helps :D

<em>~Top♥</em>

You might be interested in

ASAP

mr Goodwill [35]

Answer: A

Step-by-step explanation:

8 0

2 years ago

-10(4-10x)+5(1-10x)

Ugo [173]

The answer is 50x-35.hope this helps.if it does please mark brainliest

3 0

3 years ago

Read 2 more answers

What problem types can be solved using law of sines?

aev [14]

Let's take a triangle ABC, with a, b, and c the sides length, he law of sine is:

a/sin A =b/sin B = c/sin C
If we know the value of 2 angles and one side or the value of 2 sides and one angle, we can calculate all the elements of the triangle

6 0

3 years ago

Read 2 more answers

I dont really know how to do soh cah toah. please help me find x.

Ipatiy [6.2K]

First notice that the triangle with sides $x,y,a$ and the triangle with sides $z,a+b,x$ are similar. This is true because the angle between sides $x,y$ in the smaller triangle is clearly $30^\circ$ , while the angle between sides $y,z$ in the larger triangle is clearly $60^\circ$ . So the triangles are similar with sides $x,y,a$ corresponding to $a+b,z,x$ , respectively.

Now both triangles are $30^\circ-60^\circ-90^\circ$ , which means there's a convenient ratio between its sides. If the length of the shortest leg is $\ell_1$ , then the length of the longer leg is $\ell_2=\sqrt3\ell_1$ and the hypotenuse has length $\ell_3=\sqrt{{\ell_1}^2+{\ell_2}^2}=2\ell_1$ .

Since $x$ is the shortest leg in the larger triangle, it follows that $a+b=2x$ , so $a+b=15=2x\implies x=\dfrac{15}2$