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gizmo_the_mogwai [7]
3 years ago
9

If f(x) is differentiable for the closed interval [−4, 0] such that f(−4) = 5 and f(0) = 9, then there exists a value c, −4 <

c < 0 such that
f(c) = 0
f '(c) = 0
f (c) = 1
f '(c) = 1
Mathematics
1 answer:
Pavel [41]3 years ago
4 0
\bf \textit{mean value theorem}\\\\&#10;f'(c)=\cfrac{f(b)-f(a)}{b-a}\qquad &#10;\begin{cases}&#10;a=-4\\&#10;b=0&#10;\end{cases}\implies f'(c)=\cfrac{f(0)-f(-4)}{0-(-4)}&#10;\\\\\\&#10;f'(c)=\cfrac{9-5}{0+4}\implies f'(c)=\cfrac{4}{4}\implies f'(c)=1
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I really need help with this equation as soon as possible :D
viktelen [127]
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7 0
3 years ago
The drama club is selling T-shirts and caps to raise money for a spring trip. The caps sell for $5.00 each, and the T-shirts sel
Zinaida [17]

The required inequality is 5x+10y\geq 500

<em><u>Solution:</u></em>

Given that,

Cost of 1 cap = $ 5

Cost of 1 t-shirt = $ 10

Let "x" be the number of caps sold

Let "y" be the number of t-shirts sold

The drama club needs to raise at least $500.00 for the trip

Based on this information, we can frame a inequality as:

number of caps sold x cost of 1 cap + number of shirts sold x cost of 1 shirt \geq 500

Which means,

x \times 5 + y \times 10\geq 500\\\\5x + 10y\geq 500

Here we used "greater than or equal to" symbol , because club needs to raise at least $ 500

They can raise 500 or more than $ 500 also

Thus the required inequality is 5x+10y\geq 500

8 0
3 years ago
Please help i cant seem to figure this out
Ahat [919]

Answer:

117649

Step-by-step explanation:

7 to the power of 2 is 49 then bc its in () do 49 to the power of 3 = 117649

8 0
3 years ago
In how many ways can we rearrange the digits in the number 12321? With formula and not just listing the numbers.
Archy [21]

Answer:

With a 5-digit number, you have 5 choices for the first digit. There will be 4 digits left so you have 4 choices for the second digit. After you have chosen the first 2 digits there will be 3 remaining so you will have 3 choices for the third digit. Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 2 and 1

7 0
3 years ago
What is the constant term in the expression 6 x 3^y + 8x^2 + 5x + 7
serious [3.7K]

Answer:

The constant term is 7

4 0
3 years ago
Read 2 more answers
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