Answer:
a. no the graph fails the vertical line test
He drives an extra 4/10 miles you can check your work by adding 4
Answer: look at the picture
Step-by-step explanation:
I believe the fastest way to solve this problem is to take any two of the given points and to find the slope and y-intercept of the line connecting those two points.
Let's choose the 2 given points (-3,16) and (-1,12).
Going from the first point to the second, the increase in x is 2 and the increase in y is actually a decrease: -4. Thus, the slope of the line connecting these two points is m = -4/2, or m = -2.
Now use the slope-intercept formula to find the y-intercept, b.
One point on the line is (-3,16), and the slope is m = -2.
Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
Here, b comes out to 10.
So now we have the slope and the y-intercept. Write the equation:
y = mx + b becomes y=-2x+10. Which of the four given answer choices is the correct one?
A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms. This can be obtained by understanding what like radicals are.
<h3>Which sets of the radical expressions listed could be considered like terms as written?</h3>
- Radical expression: Radical expression is an equation that has a variable in a radicand (expression under the root) or has a variable with a rational exponent.
For example, √128, √16
- Like radicals: Radicals that have the same root number and radicand (expression under the root)
For example, 2√x and 5√x are like terms.
Here in the question radical expressions are given,
By definition of like radicals we get that 5∛2x and -3∛2x are like terms since root number and radicand are same, that is, root number is 3 and radicand is 2x.
Hence A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms.
Learn more about radicals here:
brainly.com/question/16181471
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