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3 years ago

Helppppppppppppppp plz

Mathematics

1 answer:

expeople1 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

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What is one hundred forty-one million,six hundred twenty thousand in standard form

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Millions thousands hundreds
141, 620, 000.

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3 years ago

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Is -¼ + 2 ¼y + 2 - y equivalent to y + 2 ?

Juliette [100K]

Answer: No

Step-by-step explanation:

$-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2$

$(-\frac{1}{4}+2)+(2\frac{1}{4}y-y)=y+2\\$

$(\frac{(-1)+(4)(2)}{4})+(\frac{9}{4}y-y)=y+2$

$(\frac{-1+8}{4})+(\frac{(9)(1)-(4)(1)}{4} )y=y+2$

$(\frac{7}{4})+(\frac{9-4}{4} )y=y+2$

$(\frac{7}{4})+(\frac{5}{4})y=y+2$

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3 years ago

Luke bought 256256256 ounces of strawberries. He divided them evenly between 888 different pies. How many pounds of strawberries

SIZIF [17.4K]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

$\text{256 ounces}=\frac{256}{16}\text{ pounds}=16\text{ pounds}$

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

$\text{Pounds of strawberries on each pie}=\frac{16}{8}$

$\text{Pounds of strawberries on each pie}=2$

Therefore, Luke put 2 pounds strawberries on each pie.

4 0

3 years ago

An analogy is a type of

vodomira [7]

Answer: literal language
hope this helps :)

3 0

3 years ago

I need help please.

GuDViN [60]

Answer:

The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

Step-by-step explanation:

The given expression is:

2q²-5pq-2q+5p

Make a pair of first two terms and last two terms:

(2q²-5pq) - (2q-5p)

Now factor out the common factor from each group.

Note that there is no common factor in second group. So we will take 1 as a common factor.

q(2q-5p) -1(2q-5p)

Now factor the polynomial by factoring out the G.C.F, 2q-5p

(2q-5p) (q-1)

Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

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3 years ago