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3 years ago

Given that

Mathematics

1 answer:

Ganezh [65]3 years ago

4 0

Answer:

$x^{2} -9x$

Step-by-step explanation:

I will upload a picture with my work.

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SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago

I need help with a math question ASAP!! please Below is a screenshot of the problem

Nady [450]

Answer:

Pretty sure it's B, the second one from the top

3 0

3 years ago

Read 2 more answers

15% of the students in school eat hot lunch. If 60

morpeh [17]

Answer:

400 students

Step-by-step explanation:

So 15 percent is 60 students

make an equation

0.15x=60

X stands for the total amount fo students and multiply that 0.15 becuase we know ti equals 60 and finding X will solve both problems

that’ll give you 400 students

if you check

400*0.15=60

So its correct

7 0

2 years ago

Geoff must mentally multiply –5 × 0.75 × 20. Which shows how Geoff could use the associative and commutative properties to make

joja [24]

Answer:

Step-by-step explanation:

–5 × 0.75 × 20 could be rewritten (applying the associative property) as –5 × (0.75 × 20). I chose this configuration because 0.75 * 20 is 15. Next, evaluate -5(15). This is -75. This matches Answer D.

4 0

2 years ago

Read 2 more answers

You answer 12 emails in 15 minutes. How many emails can you answer in 2 hours?

Marysya12 [62]

Answer:

Step-by-step explanation:

you divide 60 min by 15 to get 4 then u multiply 12 × 4 =48 then multiply 48 × 2=96

8 0

3 years ago