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4 years ago

How do you write 36.14 in expanded form

Mathematics

2 answers:

Andrei [34K]4 years ago

7 0

Answer:

30 + 6 + 0.1 + 0.04

Step-by-step explanation:

36.14:

3 in the tens place equals 30.

6 in the ones place equals 6.

1 in the tenths place equals 0.1.

4 in the hundredths place equals 0.04.

Which all equals:

30 + 6 + 0.1 + 0.04

katen-ka-za [31]4 years ago

4 0

Answer:

36.14=(10×3)+(6×1)+(1/10)+(4/100)

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What is range in math

dmitriy555 [2]

Answer:

The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9 − 3 = 6.

Step-by-step explanation:

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3 years ago

Cos^2(2theta)+ 2cos(2theta)+1=0

Tema [17]

Answer:

θ = π n + π/2 for n element Z

Step-by-step explanation:

Solve for θ:

1 + 2 cos(2 θ) + cos^2(2 θ) = 0

Write the left hand side as a square:

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3 years ago

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3 years ago

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3 years ago

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

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3 years ago