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Gala2k [10]
4 years ago
9

How do you write 36.14 in expanded form

Mathematics
2 answers:
Andrei [34K]4 years ago
7 0

Answer:

30 + 6 + 0.1 + 0.04

Step-by-step explanation:

<u>36.14:</u>

3 in the tens place equals 30.

6 in the ones place equals 6.

1 in the tenths place equals 0.1.

4 in the hundredths place equals 0.04.

<u>Which all equals:</u>

30 + 6 + 0.1 + 0.04

katen-ka-za [31]4 years ago
4 0

Answer:

36.14=(10×3)+(6×1)+(1/10)+(4/100)

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What is range in math
dmitriy555 [2]

Answer:

The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9 − 3 = 6.

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
Cos^2(2theta)+ 2cos(2theta)+1=0
Tema [17]

Answer:

θ = π n + π/2 for n element Z

Step-by-step explanation:

Solve for θ:

1 + 2 cos(2 θ) + cos^2(2 θ) = 0

Write the left hand side as a square:

(cos(2 θ) + 1)^2 = 0

Take the square root of both sides:

cos(2 θ) + 1 = 0

Subtract 1 from both sides:

cos(2 θ) = -1

Take the inverse cosine of both sides:

2 θ = 2 π n + π for n element Z

Divide both sides by 2:

Answer:  θ = π n + π/2 for n element Z

4 0
3 years ago
URGENT I NEED ANWSER BEFORE 7:00<br><br>6.9 x .35
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3 years ago
What name describes this shape?
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4 0
3 years ago
A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro
olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of P(A\cap B\cap C\cap D).

If two events X and Y are independent, then

P(X\cap Y)=P(X)\times P(Y)

Assume the probability of one part working does not depend on the functionality of any of the other parts.

P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)

Substitute the given values.

P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92

P(A\cap B\cap C\cap D)=0.7559226

P(A\cap B\cap C\cap D)\approx 0.756

Therefore, the probability that the machine works properly is 0.756.

7 0
3 years ago
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