3 years ago

Help please in Algebra

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

I believe the answer is D

andreev551 [17]3 years ago

3 0

The answer is D. I say this because A, C, and B are not correct. so the answer would be D

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ACT scores have a mean of 20.8 and 9 percent of the scores are above 28. The scores have a distribution that is approximately no

dimaraw [331]

Answer: 5.37

Step-by-step explanation:

Let x = ACT scores.

Given: ACT scores have a mean of 20.8 and 9 percent of the scores are above 28. The scores have a distribution that is approximately normal.

i.e. P(X>28)=0.09 (i)

Now,

$P(X>28)=P(\dfrac{X-\mu}{\sigma}>\dfrac{28-20.8}{\sigma})\\\\= P(z>\dfrac{7.2}{\sigma})\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]$ (ii)

One -tailed z value for p-value of 0.09 =1.3408 [By z-table]

From (i) and (ii)

$\dfrac{7.2}{\sigma}=1.3408\\\\\Rightarrow\ \sigma=\dfrac{7.2}{1.3408}\\\\\Rightarrow\ \sigma=5.37$

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WARRIOR [948]

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