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Ronch [10]
3 years ago
10

Solve the problem as directed. The volume (v) of a sphere varies directly as the cube of its diameter (d). Write this statement

in algebraic language, using an equation with the variables c, v, and d.
Mathematics
2 answers:
fredd [130]3 years ago
5 0
<span>Answer: a million) d/154 = 14/40 4 bypass multiply: 44d = 2156 d = 40 9 2) i will apply ^ to signify exponents, because of the fact superscript numbers do no longer artwork nicely at right here. c is continuous and represents the ratio of v to d^3 the dating is, subsequently: v = cd^3 3) enable w = wages for 5 adult adult males w/5 = $fifty two.08/3 bypass multiply: 3w = $260.40 w = $86.80 4) enable x = value of a 9-minute call x/9 = $0.ninety/6 bypass multiply: 6x = $8.10 x = $a million.35 5) i'm no longer completely confident what's being asked for in this one, yet i'm vulnerable to circulate with: P/a million = V/ok or P:a million = V:ok</span>
RoseWind [281]3 years ago
3 0

Since we know that our given are:

Volume which is denoted by v; and

Diameter which is denoted by d.

 Since we are looking for an equation:

The question clearly states that "v varies directly as the cube of d" means that for some constant c, 
v = c d^3 [where ^ specifies the 3 is an exponent] 
so 
c = v / (d^3)

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What is the value of x in the equation. 8 x - 2 y= 48 when y =4​
goldfiish [28.3K]

\qquad❄️\boxed{\bf x = 7}\\\\

We are given –

\qquad \twoheadrightarrow\bf 8x -2 y =48

  • And also value of y's given. So, just put the value of y in the given equation.

___________________________________

\qquad \purple{\twoheadrightarrow\bf 8x -2 y =48}

\qquad \twoheadrightarrow\sf  8x - \underbrace{2 \times 4} =48

\qquad \twoheadrightarrow\sf  8x - 8 =48

\qquad \twoheadrightarrow\sf  8x = 48 +8

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\qquad \purple{\twoheadrightarrow\bf x= 7}

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