9514 1404 393
Answer:
a8 = 4
Step-by-step explanation:
Put 8 where n is and do the arithmetic.
a8 = (1/2)(8) = 8/2 = 4
The 8th term of this arithmetic sequence is 4.
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
c
Step-by-step explanation: all you have to do is work it out
Answer:
(1,2)
Step-by-step explanation:
thats the point of intersection so they have the same outcome
I'm a little confused by the question but I hope this helps :)
Answer:
45 %
Step-by-step explanation:
Time left until Christmas = 2 weeks
= 2 * 7 days [since 1 week = 7 days]
= 14 days
Number of days in December = 31
Percentage of the month left before Christmas = 
= 
= 0.45 * 100
= 45 %
