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3 years ago

Write a real-world problem that can be represent 3x + 6 > 27

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

3 customers times the amount of cups plus 6 dollars in change is less than 24.

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What is the slope of the line that passes through the points (-3,12) and (6,24)?

Irina18 [472]

Answer: slope = 4/3

Step-by-step explanation:

(24-12)/(6- -3)

= 12/9

= 4/3

7 0

3 years ago

Use the frequency table to find the mean number of working TV sets in students' homes. (picture attached)

LenaWriter [7]

The correct option is : 2

Explanation

For finding the mean number of working TV sets, we need to divide the total number of TV sets by the total frequency.

Now for finding the total number of TV sets, first we will multiply each number of TV sets by it's frequency and then sum up all the results.

So, the total number of TV sets

$=(0*1)+(1*8)+(2*9)+(3*4)+(4*3) \\\\ =0+8+18+12+12=50$

and total frequency $=1+8+9+4+3= 25$

Thus, the mean number of working TV sets $= \frac{50}{25}=2$

5 0

3 years ago

Need help solving please!!!

Sidana [21]

Answer:

Ha goood luck

Step-by-step explanation:

Ha goog

5 0

3 years ago

Suppose the scores of seven members of a women’s golf team are 68, 62, 60, 64, 70, 66, and 72. Find the mean, median, and midran

grin007 [14]

Mean - add up all of the scores, and divide it by the number of members:

68 + 62 + 60 + 64 + 70 + 66 + 72 = 462
462 / 7 = 66

ANSWER: The mean is 66

Median - write out all the numbers in order, and select the middle value:

60, 62, 64, 66, 68, 70, 72

ANSWER: As you can see, 66 is the middle value.

Midrange - find the mean (average) of the smallest and largest number:

Largest number: 72
Smallest number: 60

Midrange: 72 + 60 = 132
132 / 2 = 66

ANSWER: So the midrange is 66

4 0

3 years ago

The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,

Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of $LT^{-1}$

Dimensions of C are of $LT^{-2}$

Step-by-step explanation:

The given equation is

$x(t)=A+Bt+Ct^{2}$

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

Thus

Dimensions of A = [L]

Dimensions of Bt = [L]

$Bt=[L]\\\\$ $[B][T]=[L]$ $\\\\\therefore [B]=LT^{-1}$

Similarly

Dimensions of $Ct^{}2 = [L]$

$Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}$

4 0

3 years ago