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Sonja [21]
3 years ago
6

Of interest is to test the hypothesis that the mean length of all face-to-face meetings and the mean length of all Zoom meetings

are the same, versus the alternative hypothesis that the mean length of all face-to-face meetings is less than the mean length of all Zoom meetings. State the appropriate null and alternative hypotheses that should be tested.
Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Answer:

Null hypothesis: \mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n

Alternative hypothesis: \mu_i \neq \mu_j , i,j =1,2,....,n

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

Step-by-step explanation:

For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:

Null hypothesis: \mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n

Alternative hypothesis: \mu_i \neq \mu_j , i,j =1,2,....,n

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

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bezimeni [28]
Add 2x to both sides,
3x+9=18
Subtract 9 from both sides. 3x=9
Divide both sides by 3. 
x=3
6 0
3 years ago
One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd
mart [117]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

Remember that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

<em>Find the slope of the first line</em>

we have the points

(-3,-1) and (1,-9)

substitute in the formula

m_1=\frac{-9+1}{1+3}

m_1=\frac{-8}{4}

m_1=-2

<em>Find the slope of the second line</em>

we have the points

(1,4) and (5,6)

substitute in the formula

m_2=\frac{6-4}{5-1}

m_2=\frac{2}{4}

Simplify

m_2=\frac{1}{2}

<em>Compare the slopes</em>

m_1=-2

m_2=\frac{1}{2}

Find out the product

m_1*m_2=(-2)(\frac{1}{2})=-1

therefore

The lines are perpendicular

8 0
3 years ago
Read 2 more answers
Find one value of xxx that is a solution to the equation (2x+3) 2 −6x−9=0
vesna_86 [32]

(2x+3) ^2 −6x−9=0

(2x+3) (2x+3) −6x−9=0

Foil

4x^2 +6x+6x+9-6x-9=0

4x^2 +12x+9-6x-9=0

Combine like terms

4x^2 +6x=0

factor out 2x

2x(2x+3)=0

2x=0  2x+3=0

x=0       2x=-3

              x=-3/2

Answer x=-3/2, 0


3 0
3 years ago
Please help me with this
Sonja [21]
The answer to your question is D) √5x/5x.

I hoped this helped!
6 0
3 years ago
Find the outlier in the set of data.(
Ksivusya [100]
The answer is A (38)
5 0
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