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Sonja [21]
3 years ago
6

Of interest is to test the hypothesis that the mean length of all face-to-face meetings and the mean length of all Zoom meetings

are the same, versus the alternative hypothesis that the mean length of all face-to-face meetings is less than the mean length of all Zoom meetings. State the appropriate null and alternative hypotheses that should be tested.
Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Answer:

Null hypothesis: \mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n

Alternative hypothesis: \mu_i \neq \mu_j , i,j =1,2,....,n

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

Step-by-step explanation:

For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:

Null hypothesis: \mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n

Alternative hypothesis: \mu_i \neq \mu_j , i,j =1,2,....,n

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

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Step-by-step explanation:

For median,

Arrange your numbers in numerical order.

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If you have an odd number, divide by 2 and round up to get the position of the median number.

If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

Source: https://www.verywellmind.com/how-to-identify-and-calculate-the-mean-median-or-mode-2795785

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For May apply same concept and you get median to be 2.25.

Median difference is 3.25-2.25 = 1

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3 years ago
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Step-by-step explanation:

First find how many games they need to have 90% by multiplying .9(30)=27

then, 15(.8)=12

Then 27-12=15

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