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Gelneren [198K]
3 years ago
6

Seven less than twice a number is greater then five more than the same number. which integer satisfies this inequality?

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0
13
just use trial and error. PLUS since *the integer x 2* needs to be greater than that *integer + 5*, you already know that the number needs to be greater than 5.
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alex41 [277]

Answer:

1. 30°

2.90°

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Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

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Step-by-step explanation:

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