Question

Seventy pupils (37 boys and 33 girls) are divided into two groups, with forty pupils in Group I and thirty pupils in Group II. How many more boys are there in Group I than there are girls in Group II?

Answer 1

Answer:

7 more boys

Step-by-step explanation:

Given

$Total = 70$

$Boys = 37$

$Girls = 33$

$Group\ 1 = 40$

$Group\ 2 = 30$

Required

Number of more boys than girls in group 2

Represent the number of boys in group 1 with B and the number of girls with G.

So:

$B + G = 40$

Make G the subject

$G = 40 - B$

The number of girls in group 2 will be:

Total number of girls (33) - number of girls in group 1(40 - B)

So, we have:

$Group\ B\ Girls = 33 -(40 - B)$

$Group\ B\ Girls = 33 -40 + B$

$Group\ B\ Girls = -7 + B$

$Group\ B\ Girls = B-7$

This means that there are 7 more boys than girls