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Oksanka [162]
3 years ago
8

You can trim the grass using a lawnmower at a rate of 80 square feet per minute. You can use a string trimmer at a rate of 20 sq

uare feet per minute. The yard has an area of 2800 square feet. If you use the trimmer for 20 minutes, how many minutes will you use the lawnmower?
a 60
b 80
c 50
d 30
Mathematics
1 answer:
docker41 [41]3 years ago
5 0
So first its 20 x 20 which is 400 so then the lawnmower does 80 per min so 80 x 5 and u get 400

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Which of the following sets of ordered pairs represents a function?
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Answer: your answer is A) & D)

Step-by-step explanation:     Hope this helps :)

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2 years ago
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Carissa also has a sink that is shaped like a half sphere. The sink has a volume of 4000/ 3 * π in 3. One day, her sink clogged.
givi [52]

Answer:

Part a) 119 cups

Part b) 30 cups

Step-by-step explanation:

Part a)

step 1

Find the volume of the conical cup with a diameter of 4 in. and a height of 8 in

The volume of the cone (cup) is equal to

V=\frac{1}{3}\pi r^{2}h

we have

r=4/2=2\ in ----> the radius is half the diameter

h=8\ in

assume

\pi =3.14

substitute

V=\frac{1}{3}(3.14)(2^{2})8=33.49\ in^3

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

so

\frac{4,000}{33.49}= 119\ cups

Part b)

step 1

Find the volume of the conical cup with a diameter of 8 in. and a height of 8 in

The volume of the cone (cup) is equal to

V=\frac{1}{3}\pi r^{2}h

we have

r=8/2=4\ in ----> the radius is half the diameter

h=8\ in

assume

\pi =3.14

substitute

V=\frac{1}{3}(3.14)(4^{2})8=133.97\ in^3

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

so

\frac{4,000}{133.97}= 30\ cups

7 0
3 years ago
If x = 3 cm and z = 5 cm, what is the length of y?
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D.

Step-by-step explanation:

8 0
2 years ago
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Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0
3 years ago
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I think $43.57 Bc 41.90 times .04 is 16.76 then move the decimal, and add 41.90+1.67=43.57
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2 years ago
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