The graph of a linear function f passes through the point (3, -10) and has a slope of -5. What is the zero ?
1 answer:
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FORMULA:
AREA= AC x h
----------------------
2
PERIMETER= AB+BC+CA
AREA = SQUAREROOT
S(S-AB)(S-BC)(A-CA)
S= AB+BC+CA= P
----------------- -----
2 2
FOR THE COMPLETE SOLUTION PLEASE SEE THE PICTURE. THANKS.
AREA= AC x h
----------------------
2
PERIMETER= AB+BC+CA
AREA = SQUAREROOT
S(S-AB)(S-BC)(A-CA)
S= AB+BC+CA= P
----------------- -----
2 2
FOR THE COMPLETE SOLUTION PLEASE SEE THE PICTURE. THANKS.