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DIA [1.3K]
3 years ago
10

Can someone help me solve this equation -5(3x-4)+4=114

Mathematics
2 answers:
Arturiano [62]3 years ago
8 0
Using distributive property you would do what it is in the parentheses first. So -5(3x-4) would be -15x+20. It would be a positive 20 because you multiplied a negative with another negative. Youre equation now would be -15x+20+4=114.
Using like terms you would simplify 20 and 4 to get -15x+24=114. To get variable x alone you would subtract 24 to both sides of the equal sign to get -15x=90. Now you would just divide -15 to both sides to get x alone. So you would now get x=(-)18.2
Ahat [919]3 years ago
3 0
-15x divided by 90 is 6, not 18.2. So your answer is -6
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Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

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Subtract 56 from both sides of the equation:

x^2+y^2+8x-14y+56-56=0-56\\x^2+y^2+8x-14y=-56

Make two groups for variable "x" and variable "y":

(x^2+8x)+(y^2-14y)=-56

Complete the square:

Add (\frac{8}{2})^2=4^2 inside the parentheses of "x".

Add  (\frac{14}{2})^2=7^2 inside the parentheses of "y".

Add 4^2 and 7^2 to the right side of the equation.

Then:

(x^2+8x+4^2)+(y^2-14y+7^2)=-56+4^2+7^2\\\\(x^2+8x+4^2)+(y^2-14y+7^2)=9

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(x+4)^2+(y-7)^2=3^2

You can observe that the radius of the circle is:

r=3

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